NAME¶

stpcpy - copy a string returning a pointer to its end

SYNOPSIS¶

#define _GNU_SOURCE


#include <string.h>

char *stpcpy(char *dest, const char *src);

DESCRIPTION¶

The stpcpy() function copies the string pointed to by src (including the terminating '\0' character) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

RETURN VALUE¶

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null byte) rather than the beginning.

CONFORMING TO¶

This function is not part of the C or POSIX.1 standards, and is not customary on Unix systems, but is not a GNU invention either. Perhaps it comes from MS-DOS. Nowadays, it is also present on the BSDs.

EXAMPLE¶

For example, this program uses stpcpy() to concatenate foo and bar to produce foobar, which it then prints.

#define _GNU_SOURCE
#include <string.h>
#include <stdio.h>
int
main(void)
{


    char buffer[20];


    char *to = buffer;


    to = stpcpy(to, "foo");


    to = stpcpy(to, "bar");


    printf("%s\n", buffer);
}

BUGS¶

This function may overrun the buffer dest.

SEE ALSO¶

bcopy(3), memccpy(3), memcpy(3), memmove(3), strcpy(3), wcpcpy(3), feature_test_macros(7)

COLOPHON¶

This page is part of release 3.22 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/.